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Question
A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.
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Solution
Mass of
the given sample compound = 0.24g
Mass of boron in the given sample
compound = 0.096g
Mass of oxygen in the given
sample compound = 0.144g
%
composition of compound = % of boron and % of oxygen
Therefore % of boron = (mass of
boron)/(mass of the sample compound) x 100
= 40%
Therefore % of oxygen = (mass of
oxygen) / (mass of the sample compound) x 100
= 60%
Mass of the given sample compound = 0.24g
Mass of boron in the given sample compound = 0.096g
Mass of oxygen in the given sample compound = 0.144g
% composition of compound = % of boron and % of oxygen
Therefore % of boron = (mass of boron)/(mass of the sample compound) x 100
= 40%
Therefore % of oxygen = (mass of oxygen) / (mass of the sample compound) x 100
= 60%
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