You visited us 1 times! Enjoying our articles? Unlock Full Access!

Time of Flight

A 0.5 kg ball...

Question

A 0.5 kg ball is thrown horizontally from point A with velocity $V_{A} = 2 m / s$ . It strikes the smooth inclined plane and bounces. Take coefficient of restitution e =0.6 and $g = 10 m / s^{2}$

The speed at which it bounces from the plane is

20 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 m/s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

14 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 8 m/s
$R = V_{A} t t = 1 s e c v_{x} = c o s 30^{\circ} = \sqrt{3} m / s v_{y} = 2 s i n 30^{\circ} = 1 m / s a_{x} = - g c o s 30^{\circ} = 4.9 m / s^{2} a_{y} = - g c o s 30^{\circ} = - 4.9 \sqrt{3} m / s^{2} v_{x} = v_{x} + a_{x} t v_{y} = v_{y} + a_{y} t V = \sqrt{v_{x}^{2} + (e V y)^{2}} = 8.0 m / s$

Suggest Corrections

Similar questions

V_{A} = 2 m / s

g = 10 m / s^{2}

10 m/s

μ = 0.5

e = 0.4

1^{st}

(g = 10 {m/s}^{2})

2 kg

20 m

g = 10 {m/s}^{2}

8 m/s

0.5 sec

g = 10 {m/s}^{2}

30^{\circ}

40 m/s

60^{\circ}

(g = 10 {m/s}^{2})

Join BYJU'S Learning Program