A 0.50 gm ball carries of magnitude $10 μ C$ . It is suspended by a string in a downward electric field of intensity 300 N/C If the charge on the ball is positive, then the tension in the string is (g = 10 $m s^{- 2}$ )

5 \times 10^{- 3} N

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8 \times 10^{- 3} N

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2 \times 10^{- 3} N

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Z e r o

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Solution

The correct option is B $8 \times 10^{- 3} N$
$T = F_{g} + F_{e}$
$= M g + E q$
$= (0.5 \times 10^{- 3} \times 10) + (300 \times 10 \times 10^{- 6})$
$= (5 + 3) 10^{- 3}$
$= 8 \times 10^{- 3} N$

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A 0.50 gm ball carries of magnitude 10μC. It is suspended by a string in a downward electric field of intensity 300 N/C If the charge on the ball is positive, then the tension in the string is (g = 10 ms−2)

The correct option is B 8×10−3NT=Fg+Fe =Mg+Eq =(0.5×10−3×10)+(300×10×10−6) =(5+3)10−3 =8×10−3N

A 0.50 gm ball carries of magnitude $10 μ C$ . It is suspended by a string in a downward electric field of intensity 300 N/C If the charge on the ball is positive, then the tension in the string is (g = 10 $m s^{- 2}$ )

The correct option is B $8 \times 10^{- 3} N$
$T = F_{g} + F_{e}$
$= M g + E q$
$= (0.5 \times 10^{- 3} \times 10) + (300 \times 10 \times 10^{- 6})$
$= (5 + 3) 10^{- 3}$
$= 8 \times 10^{- 3} N$