A $0.50 L$ container is occupied by nitrogen at a pressure of $800 t o r r$ and a temperature of $0^{o} C$ . The container can only withstand a pressure of $3.0 a t m$ . What is the highest temperature $(^{o} C)$ to which the container may be heated?

505

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450

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625

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500

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Solution

The correct option is A $505$
As we know the

$\frac{P V}{T} = Canstant$

Given

$P_{i} = 800 torr = \frac{800}{760} atm$

$f_{f} = 3 atm$

$V_{i} = 0.5, V_{f} = 0.5$

$T_{i} = (273 + 0) = 273 K$

From the formula

$\frac{P_{i} V_{i}}{T_{i}} = \frac{P_{j} V_{f}}{T_{f}}$

$\frac{800 \times 0.5}{760 \times 273} = \frac{3 \times 0.5}{T}$

$T_{f} = 778 K$

$T_{f} = 505^{\circ} C$

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A 0.50 L container is occupied by nitrogen at a pressure of 800 torr and a temperature of 0oC. The container can only withstand a pressure of 3.0 atm. What is the highest temperature (oC) to which the container may be heated?

The correct option is A 505As we know the PVT= Canstant Given Pi=800 torr =800760 atm ff=3 atm Vi=0.5,Vf=0.5 Ti=(273+0)=273 K From the formula PiViTi=PjVfTf 800×0.5760×273=3×0.5T Tf=778 K Tf=505∘C

A $0.50 L$ container is occupied by nitrogen at a pressure of $800 t o r r$ and a temperature of $0^{o} C$ . The container can only withstand a pressure of $3.0 a t m$ . What is the highest temperature $(^{o} C)$ to which the container may be heated?