A $0.50 k g$ object moves in a horizontal circular track with a radius of $2.5 m$ . An external force of $3.0 N$ , always tangent to the track, causes the object to speed up as it goes around. The work done by the external force as the mass makes one revolution is:

24 J

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47 J

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58 J

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67 J

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Solution

The correct option is B $47 J$
1 rev = 2 x 2.5 x pi = 15.708 m
3 x 15.708 = 47.12 J

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A 0.50kg object moves in a horizontal circular track with a radius of 2.5m. An external force of 3.0N, always tangent to the track, causes the object to speed up as it goes around. The work done by the external force as the mass makes one revolution is:

The correct option is B 47J1 rev = 2 x 2.5 x pi = 15.708 m 3 x 15.708 = 47.12 J

A $0.50 k g$ object moves in a horizontal circular track with a radius of $2.5 m$ . An external force of $3.0 N$ , always tangent to the track, causes the object to speed up as it goes around. The work done by the external force as the mass makes one revolution is:

The correct option is B $47 J$
1 rev = 2 x 2.5 x pi = 15.708 m
3 x 15.708 = 47.12 J