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A 0.5kg bal...

Question

A $0.5 k g$ ball moving with a speed of $12 m / s$ strikes a hard wall at an angle of $30^{o}$ with the wall. It is reflected with the same speed and at the same angle, as shown in figure. If the ball is in contact with the wall for $0.25 s$ the average force acting on the wall is

A

96 N

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B

48 N

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C

24 N

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D

12 N

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Solution

The correct option is C $24 N$
$F_{a v g} = m (v_{f} - v_{i}) / t$
$v_{f} = 0 m / s$
$v_{i} = 12 m / s$
Therefore,
$F_{a v g} = m (v_{f} - v_{i}) / t$
$= 0.5 (0 - 12) / 0.25$
$= - 24 N$

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