A $1.0$ hp motor pumps out water from a well of depth $20 m$ and fills a water tank of volume $2238$ liters at a height of $10 m$ from the ground. The running time of the motor to fill the empty water tank is $(g = 10 {m s}^{- 2})$

5

minutes

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10

minutes

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15

minutes

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20

minutes

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Solution

The correct option is C $15$ minutes
Given that Volume of water to raise = $22380 / = 22380 \times 10. m$

power is defined as P=W/t

Here W= work done =mgh

$P = \frac{m g h}{t} = \frac{V P g h}{t}$

$\Rightarrow t = \frac{V P g h}{P}$

$t = \frac{22380 \times 10^{- 3} \times 10^{3} \times 10 \times 10}{10 \times 746} = 15 m i n$

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A 1.0 hp motor pumps out water from a well of depth 20m and fills a water tank of volume 2238 liters at a height of 10m from the ground. The running time of the motor to fill the empty water tank is (g=10ms−2)

The correct option is C 15 minutesGiven that Volume of water to raise = 22380/=22380×10.mpower is defined as P=W/tHere W= work done =mghP=mght=VPght⇒t=VPghPt=22380×10−3×103×10×1010×746=15min

A $1.0$ hp motor pumps out water from a well of depth $20 m$ and fills a water tank of volume $2238$ liters at a height of $10 m$ from the ground. The running time of the motor to fill the empty water tank is $(g = 10 {m s}^{- 2})$