A 1.0 hp motor pumps out water from a well of depth and fills a water tank of volume 2238 litres at a height of 10 m from the ground. The running time of the motor to fill the empty water tank is

5 minutes

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10 minutes

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15 minutes

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20 minutes

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Solution

The correct option is C 15 minutes
P = $\frac{m g h}{t}$
$\Rightarrow$ 746 = $\frac{2238 \times 10 \times 30}{t}$
$\Rightarrow$ t = 900 s = 15 minutes

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Similar questions

A 10 H.P. motor pumps out water from a well of depth 20m and fills a water tank of volume 22380 litres at a height of 10m from the ground. The running time of the motor to fill the empty water tank is ( $g = 10 m s^{- 2}$ )

Q. A

1.0

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20 m

and fills a water tank of volume

2238

litres at a height of

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from the ground. The running time of the motor to fill the empty water tank is

(g = 10 m s^{- 2})

Q. A

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and fills a water tank of volume

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liters at a height of

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from the ground. The running time of the motor to fill the empty water tank is

(g = 10 {m s}^{- 2})

Q. A motor is used to lift water from a well of depth 10 m and to fill water tank of volume 30 m

^{3}

10 minutes. The tank is at height of 20 m above ground. If 20% of energy is wasted, the power of the motor is (in kW)

A pipe is connected to a tank. The water flows out from the tank through the pipe at the rate of $64 \frac{m^{3}}{m i n u t e s}$ . Find the time taken by the pipe to empty the volume of $1024 m^{3}$ (in minutes).

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A 1.0 hp motor pumps out water from a well of depth and fills a water tank of volume 2238 litres at a height of 10 m from the ground. The running time of the motor to fill the empty water tank is

The correct option is C 15 minutesP = mght ⇒ 746 = 2238×10×30t ⇒ t = 900 s = 15 minutes

The correct option is C 15 minutes
P = $\frac{m g h}{t}$
$\Rightarrow$ 746 = $\frac{2238 \times 10 \times 30}{t}$
$\Rightarrow$ t = 900 s = 15 minutes