CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A 1.0 kg block collides with a horizontal light spring of force constant 2 N/m. The block compresses the spring 4m from the rest position. Assuming that the coefficient of kinetic friction between the block and the horizontal surface is 0.25, what was the speed of the block at the instant of collision?


A
52 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
52m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
25 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 52m/s

So let's see what is happening

K=2 N/m
X=4m
M=0.25

Assume block hits with velocity V m/s
The spring will compress till the point the block stops.
Also friction is acting all this while.
Applying work energy theorem:
(Only friction and spring forces are acting)
Wfr+Wsp=ΔKE

μmgs12kx2=012mu2μmgs+12kx2=12mu2Substituting the given values in the above equationu=52 m/s

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Rubbing It In: The Basics of Friction
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon