1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A 1.0 kg block collides with a horizontal light spring of force constant 2 N/m. The block compresses the spring 4m from the rest position. Assuming that the coefficient of kinetic friction between the block and the horizontal surface is 0.25, what was the speed of the block at the instant of collision?

A
52 m/s
No worries! Weāve got your back. Try BYJUāS free classes today!
B
52m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
25 m/s
No worries! Weāve got your back. Try BYJUāS free classes today!
D
none of these
No worries! Weāve got your back. Try BYJUāS free classes today!
Open in App
Solution

## The correct option is B √52m/sSo let's see what is happening K=2 N/m X=4m M=0.25 Assume block hits with velocity V m/s The spring will compress till the point the block stops. Also friction is acting all this while. Applying work energy theorem: (Only friction and spring forces are acting) Wfr+Wsp=ΔKE −μmgs−12kx2=0−12mu2μmgs+12kx2=12mu2Substituting the given values in the above equationu=√52 m/s

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Rubbing It In: The Basics of Friction
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program