Question

A $1.00\times {10}^{-20}kg$ particle is vibrating with simple harmonic motion with a period of $1.00\times {10}^{-5}sec$ and a maximum speed of $1.00\times {10}^{3}m/s$. The maximum displacement of the particle is

• A. 1.59 mm
• B. 1.00 m
• C. 10 m
• D. None of these

Answer 1

The correct option is A

1.59 mm

$v_{max}=a\omega =a\times \frac{2\pi }{T}\Rightarrow a=\frac{v_{max}\times T}{2\pi }$

$a=\frac{1.00\times {10}^3\times (1\times {10}^{-5})}{2\pi }=1.59mm$