CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A 1.24 M aqueous solution of KI has density of 1.15g/cm3 . What is the percentage composition of solute in the solution?

A
17.89
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
27.89
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
37.89
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
47.89
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 17.89
1.24 M aqueous solution of KI means 1.24 moles of KI in 1 litre of solution.

Given,
Density of solution =1.15 gcm3

Volume of solution =1 L or 1000 cm3

Mass of solution =Density×volume

=1.15×1000

=1150 g

Mass of solute =1.24×166=205.8 g

Percentage composition of solute =Mass of solute Mass of solution×100

=205.81150×100

=17.89%

Hence, option A is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Mole Concept
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon