$A (- 1, 3), B (4, 2)$ and $C (3, - 2)$ are the vertices of a triangle.Find the coordinates of the centroid G of the triangle.

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Solution

Co-ordinates Of Centroid:
$x_{c e n t r o i d} = \frac{x_{1} + x_{2} + x_{3}}{3}$
$⟹ x_{c e n t r o i d} = \frac{- 1 + 4 + 3}{3} = 2$
$y_{c e n t r o i d} = \frac{y_{1} + y_{2} + y_{3}}{3}$
$⟹ y_{c e n t r o i d} = \frac{3 + 2 - 2}{3} = 1$

Thus $G (x, y) = (2, 1)$

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A(−1,3),B(4,2) and C(3,−2) are the vertices of a triangle.Find the coordinates of the centroid G of the triangle.

Co-ordinates Of Centroid:xcentroid=x1+x2+x33⟹xcentroid=−1+4+33=2ycentroid=y1+y2+y33⟹ycentroid=3+2−23=1Thus G(x,y)=(2,1)

$A (- 1, 3), B (4, 2)$ and $C (3, - 2)$ are the vertices of a triangle.Find the coordinates of the centroid G of the triangle.

Co-ordinates Of Centroid:
$x_{c e n t r o i d} = \frac{x_{1} + x_{2} + x_{3}}{3}$
$⟹ x_{c e n t r o i d} = \frac{- 1 + 4 + 3}{3} = 2$
$y_{c e n t r o i d} = \frac{y_{1} + y_{2} + y_{3}}{3}$
$⟹ y_{c e n t r o i d} = \frac{3 + 2 - 2}{3} = 1$

Thus $G (x, y) = (2, 1)$