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Reactivity Trends (Group 2)

A 1.50 g of a...

Question

A 1.50g of an ore containing silver was dissolved and all of the Ag⁺was converted into 0.24 g of Ag2S .what was the percentage of silver in the ore

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Solution

Find moles and mass of Ag in Ag2S:

0.24 g Ag2S / 247.8 g/mol = 9.685X10^-4 mol

(9.685X10^-4 mol Ag2S) X (2 mol Ag/1 mol AgS) X 107.9 g/mol =0.209 g Ag

%Ag in ore = (0.209 g Ag / 1.50 g ore) X 100 =13.9% Ag

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