A 1.8 km long and 8 m wide road is to be laid with road metal of 15 cm thickness. How many cubic metres of road metal will be required for the purpose?

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Solution

Length of the road = 1.8 km = 1800 m (1 km = 1000 m)
Breadth of the road = 8 m
Thickness of the road = 15 cm = 0.15 m $(1 cm = \frac{1}{100} m)$
Volume of the road metal required = length of road × breadth of road × thickness of road metal
= 1800 × 8 × 0.15 m³
= 2160 m³
∴ Volume of the road metal required is 2160 m³ .

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