$A_{1}$ and $A_{2}$ are two ores of metal $M .$

C u_{2} S, C u (O H)_{2} . C u C O_{3}

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C a C O_{3}, C u_{2} S

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C u_{2} S, C a C O_{3}

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C u (O H)_{2} . C u C O_{3}, C u_{2} S

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Solution

The correct option is D $C u (O H)_{2} . C u C O_{3}, C u_{2} S$
$A_{1}$ is basic copper carbonate $(C u (O H)_{2} . C u C O_{3})$ while $A_{2}$ is $C u_{2} S .$ The confirmatory reactions are:

$C u C O_{3} . C u (O H)_{2} Δ - \to C u O B l a c k + C O_{2} ↑ H_{2} O$

$C u C O_{3} . C u (O H)_{2} d i l . H C l - ---- \to C u C l_{2} + C O_{2} ↑ + H_{2} O$

$C u C l_{2} K I - - \to C u_{2} I_{2} ↓ (D) + K C l + I_{2}$

$C u_{2} S + C u_{2} O \to C u + S O_{2} ↑$

$S O_{2}$ is a reducing gas that gives green colour with acidified $K_{2} C r_{2} O_{7} .$
$3 S O_{2} + K_{2} C r_{2} O_{7} + H_{2} S O_{4} \to K_{2} S O_{4} + C r_{2} (S O_{4})_{3} Green + 4 H_{2} O$

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