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Question

A 1g sample of H2O2 solution containing x% H2O2 by mass requires x cm3 of a KMnO4 solution for complete oxidation under acidic condition. Calculate the normality of KMnO4 solution.

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Solution

Given, 1g of sample of H2O2 has x% H2O2 by mass
This means 100g sample has x gm of H2O2
1g sample has 1g×xgm100gmH2O2(1)
Now, Volume of KMnO4 used for neutralization=xcm3
We know,
At equivalence,
No. of gm equivalents of H2O2=No. of gm equivalents of KMnO4(2)
N1V1H2O2=N2V2KMnO4
x100×17=NiX1000 [Normality=WtEq.Wt1000Vinml]
[EquivalentWeightofH2O2=342=17]
N2=1017=0.588N
Normality of KMnO4=0.588N

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