Question

A 1 h.p. electric motor operates a pump continuously. The work performed by the motor in one day is

• A. 18 kWh
• B. 36 kWh
• C. 54 kWh
• D. 72 kWh

Answer 1

The correct option is A 18 kWh

Solution: Mathematically, $1h.p.=746W$

Also, 1 kW = $1000W$

So, $1h.p.=0.746kW$

Work done by the motor in one day or 24 hrs is given by,

$E=P\times t$

where, E denotes electrical energy,

P denotes the power in kilowatt and

t denotes the time in hours

Substituting the values in the above equation we get,

$E=0.746kW\times 24$

$E=18kWh$

Hence, the correct option is (A).