The correct option is D 0.0004
Given data: 1 hr, 10 cm rainfall has a return period of 50 years i.e. T = 50 yrs.
The probability of occurrence of an event, r times in 'n' successive years
=nCrPrqn−r
Where,
P = probability of occurrence of
an event
=(1T)
q = probability of non-occurrence
=1−(1T)
Probability of occurrence of 1hr, 10 cm rainfall or more, occurring in each of two successive years
=2C2p2q2−2
=2C2p2q0
=1×(150)2×1=0.0004