Question

A $1$ kg ball drops vertically onto the floor with a speed of $25$ m/s and rebounds with a speed of $10$ m/s What is the impulse acting on the ball?

Answer 1

Given that $v=25m/s$

$4u=10m/s$

$m=1kg$

Impulse ?

We know that,

$v=u+gt$ (Newton's 1st equation of motion)

where v = final velocity

u = initial velocity

g = acceleration due to gravity

t = time

$25=10+9.8\times t$

$t=1.53$

Now

Impulse $=Force\times \Delta time$

$=mgh\times \Delta time$

$=1\times 9.8\times h\times 1.53$

$=14.994\times h$ (approx)