Question

A 1 kg block is resting on a surface with coefficient of friction $\mu =0.1$. A force of 0.8 N is applied to the block as shown in the figure. The friction force is

• A. 0
• B. 0.8 N
• C. 0.98 N
• D. 1.2 N

Answer 1

The correct option is B 0.8 N


$\text{Friction force}=\mu \times N$
$\Sigma F_v=0$
$\therefore N-mg=0$
$N=mg=1\times 9.81$

$\text{Friction force}=\mu \times N=0.1\times 9.81$
$=0.981N$

Since applied force is less than friction force hence friction force acting on the body at equilibrium is 0.8 N.