CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A 1 kg block situated on a rough incline is connected to a spring of spring constant 100 N m–1 as shown in Fig. 6.17. The block is released from rest with the spring in the unstretched position. The block moves 10 cm down the incline before coming to rest. Find the coefficient of friction between the block and the incline. Assume that the spring has a negligible mass and the pulley is frictionless.

Open in App
Solution

Mass of the block, m = 1 kg

Spring constant, k = 100 N m–1

Displacement in the block, x = 10 cm = 0.1 m

The given situation can be shown as in the following figure.

At equilibrium:

Normal reaction, R = mg cos 37°

Frictional force, f R = mg sin 37°

Where, μ is the coefficient of friction

Net force acting on the block = mg sin 37° – f

= mgsin 37° – μmgcos 37°

= mg(sin 37° – μcos 37°)

At equilibrium, the work done by the block is equal to the potential energy of the spring, i.e.,


flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Prerequisite: Intuition for Work Done
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon