A $1 k g$ body falls vertically with a speed of $25 m / s$ and rebounds with a speed of $10 m / s$ . If the time for which the ball is in contact with the ground is $1 m s$ , what is the contact force on the body by the ground?

35 k N

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25 k N

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15 k N

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40 k N

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Solution

The correct option is A $35 k N$
Taking upward direction as positive, $I = Δ p = m (\to v - \to u)$
$= 1 [10 - (- 25)]$ = $35 N s$
Contact force, $\to F = \frac{Δ P}{Δ t} = \frac{35}{1 \times 10^{- 3}} = 35 k N$

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A 1 kg body falls vertically with a speed of 25 m/s and rebounds with a speed of 10 m/s. If the time for which the ball is in contact with the ground is 1 ms, what is the contact force on the body by the ground?

The correct option is A 35 kNTaking upward direction as positive, I=Δp=m(→v−→u) =1[10−(−25)] = 35 Ns Contact force, →F=ΔPΔt=351×10−3=35 kN

A $1 k g$ body falls vertically with a speed of $25 m / s$ and rebounds with a speed of $10 m / s$ . If the time for which the ball is in contact with the ground is $1 m s$ , what is the contact force on the body by the ground?

The correct option is A $35 k N$
Taking upward direction as positive, $I = Δ p = m (\to v - \to u)$
$= 1 [10 - (- 25)]$ = $35 N s$
Contact force, $\to F = \frac{Δ P}{Δ t} = \frac{35}{1 \times 10^{- 3}} = 35 k N$