1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A 1 kg mass of clay, moving with a velocity of 10ms, strikes a stationary wheel and sticks to it. The solid wheel has a mass of 20 kg and a radius of 1 m. Assuming that the wheel is set into pure rolling motion, the angular velocity of the wheel immediately after the impact is approximately

A
Zero
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is B 13rad/s In this question we need to neglect the mass of clay w.r.t. mass of wheel. We can't conserve linear momentum as friction is there so we will conserve angular momentum about the point of the wheel which is in contact with the surface. (because torque about A of all forces is zero) Taking both clav and wheel as a system. Li=Lf (about A) Li=mvr=1×10×1=10 Lf=mvcmf+Iω =20×rω×r+mr22ω =20×1×ω×1+202×12×ω Li=Lf 10=20ω+10ω ⇒10=30ω or ω=1030=13rad/s

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Angular Impulse and Angular Momentum
ENGINEERING MECHANICS
Watch in App
Join BYJU'S Learning Program