A $1 m$ long uniform beam is balanced as shown. Calculate the force F.

2 N

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3 N

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7 N

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11 N

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Solution

The correct option is D $11 N$
Moment of force $M =$ force $\times$ perpendicular distance from pivot
For the balanced beam, the net moment of force on left side of pivot is equal to the net moment of force on right side.
Thus, $5 N (50 - 10) c m = F (60 - 50) c m + (3 N) (80 - 50) c m$
or $20 = F + 9$ or $F = 11 N$

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