wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A 1μF and a 2μF capacitor are connected in series across a 1200V supply. The charged capacitors are disconnected from the line and from each other and are now reconnected with the terminals of like sign together. Find the final charge on each capacitor and the voltage across each capacitor :

A
Charges on capacitors are 1400/3μC and 3200/3μC, and the potential difference across each capacitor is 1600/3V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Charges on capacitors are 1600/3μC and 3200/3μC, and the potential difference across each capacitor is 1600/3V
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Charge on each capacitor is 1600μC and potential difference across each capacitor is 800V.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Charge and potential difference across each capacitor are zero.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B Charges on capacitors are 1600/3μC and 3200/3μC, and the potential difference across each capacitor is 1600/3V
1200q1q2=0orq=800μC
Charge on each capacitor is 800μC.
V1=qC1=8001=800V
V2=qC2=8002=400V
q1+q2=1600.......(i)
Also q11q22=0
or q2=2q1
From Eq (i), 3q1=1600orq1=16003μC
3q2=32003μC
V=q1+q2C1+C2=16003V

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon