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Question

A 1μF capacitor is charged to 200 V and then connected in parallel (+ve to +ve) with a 4μF capacitor charged to 100 V. The resultant potential difference is :


A
120 V
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B
60 V
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C
180 V
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D
150 V
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Solution

The correct option is A 120 V
Total charge of the system =C1V1+C2V2=600μC
Since the capacitors are connected in parallel , the potential across them should be the same. Let the charge across 1μF capacitor be qμC.
q/1=(600q)/45q=600q=120
Potential across the capacitors =Q/C=120V

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