Question

A $1\mu \text{F}$ capacitor holding a charge of $1\times {10}^{-5}\text{C}$ is connected to a $10\Omega$ resistor via a switch. What curent will flow after the switch is closed?

• A. $10\text{A}$
• B. ${10}^{-5}\text{A}$
  
• C. $1\text{A}$
  
• D. $0\text{A}$
  

Answer 1

The correct option is C $1\text{A}$


The voltage across the capacitor is,

$V=\frac{Q}{C}=\frac{1\times {10}^{-5}}{1\times {10}^{-6}}=10\text{V}$

Thus, the current flowing through the resistor after the switch is closed will be,

$I=\frac{V}{R}=\frac{10}{10}=1\text{A}$

Hence, option $\left(c\right)$ is correct.