A 1μF capacitor is connected in the circuit shown below. The emf of the cell is 3V and internal resistance is 0.5Ω. The resistors R1 and R2 have values 4Ω and 1Ω respectively. The charge on the capacitor in steady state must be
A
1μC
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B
2μC
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C
1.33μC
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D
zero
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Solution
The correct option is B2μC In steady state, current in the branch containing the capacitor is zero and hence, emf E=3 V is shared between internal resistance (r=0.5Ω) and R2 in the ratio of their resistance.
Voltage across R2 is ER2R2+r=2Volts = Voltage across capcitor.