Question

A 1-$\varphi$ full bridge inverter has source voltage of 230 V dc and T = 1 $\mu s$ . The load consists of RLC in series with
$R=1.2\Omega ,\omega L=8\Omega ,\frac{1}{\omega C}=7\Omega$
Power delivered to load due to fundamental component is ______kW.

Answer 1

$V_{01}=\frac{4V_s}{\pi \sqrt{2}}=\frac{4\times 230}{\pi \sqrt{2}}=207.1V$

$Z_1=\sqrt{R_1^2+{(\omega L-\frac{1}{\omega C})}^2}$

$=\sqrt{{1.2}^2+(8-7{)}^2}=1.562\Omega$

$I_{01}=\frac{V_{01}}{Z_1}=\frac{207.1}{1.562}=132.586$ A

Power delivered $P_{01}=I_{01}^{2}R$

$=(132.586{)}^2\times 1.2=21.094$ kW