Question

A 1-Q resistor is connected in parallel to a 10 - Q resistor . Calculate the equivalent resistance.

Answer 1

Dear Student,

$$\begin{gathered} 1\mathrm{\Omega }\mathrm{resistor}\mathrm{is}\mathrm{connected}\mathrm{parallel}\mathrm{with}10\mathrm{\Omega }\mathrm{resistor}.\mathrm{Equivalent}\mathrm{resistance}\mathrm{is}, \\ \frac{1}{\mathrm{R}}=\frac{1}{1}+\frac{1}{10} \\ \frac{1}{\mathrm{R}}=\frac{10+1}{10} \\ \frac{1}{\mathrm{R}}=\frac{11}{10} \\ \mathrm{R}=\frac{10}{11}\mathrm{\Omega } \end{gathered}$$