A 1kg particle strikes a wall with a velocity 1m/s at an angle 30∘ and reflects at the same angle in 0.1 second, then the force applied by the wall on the particle will be
A
30√3N
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B
0
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C
40√3N
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D
10√3N
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Solution
The correct option is D10√3N Change in momentum of the ball perpendicular to the wall =m[vcosθ−(−vcosθ)] =2mvcosθ =2×1×1×cos30∘=2×√32=√3,
Rate of change of momentum =Change of momentumtime =√30.1=10√3
This will be equal to force, so force =10√3 N