Question

A $10.0$W electrical heater is used to heat a container filled with $0.5$kg of water. It is found that the temperature of the water and the container rose by $3$K in $15$ minutes. The container is then emptied, dried, and filled with $2$kg of an oil. It is now observed that the same heater raises the temperature of the container-oil system by $2$ K in $20$ minutes. Assuming no other heat losses in any of the processes, the specific heat capacity of the oil is$?$

• A. $2.5\times {10}^{3}J{K}^{-1}k{g}^{-1}$
• B. $5.1\times {10}^{3}J{K}^{-1}k{g}^{-1}$
• C. $3.0\times {10}^{3}J{K}^{-1}k{g}^{-1}$
• D. $1.5\times {10}^{3}J{K}^{-1}k{g}^{-1}$

Answer 1

The correct option is C $3.0\times {10}^{3}J{K}^{-1}k{g}^{-1}$

total heat supplied in 20 min is $20\times 60\times 10=2\times c\times 2$

c=$3\times {10}^{3}J{K}^{-1}k{g}^{-1}$