A 10 henry inductor is carrying a current 2A. Rate at which the current be changed so that an e.m.f. of 100V is induced is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B

Given $E = 100 V, L = 10 H$

$∴ 100 = 10 \times \frac{d I}{d t} o r \frac{d I}{d t} = 10 A s^{- 1}$

Suggest Corrections

Similar questions

Q. An e.m.f. of 20 volt is applied in a circuit containing 5 henry inductance and 10 ohm resistance. The ratio of the currents at time

t = \infty

and at t = 1 second is

A long wire carrying a current of 20A is fixed. Another long wire AB is to be balanced mid-air a distance 2cm. Find the magnitude of the current in AB. Also find the angular frequency of SHM. If AB is slightly disturbed from this position. Given the mass per unit length of the wires is $10^{- 6} k g / m$

Q. An e.m.f. of 15 volt is applied in a circuit containing 5 henry inductance and 10 ohm resistance. The ratio of the currents at time

t = \infty

and at t =1 second is

Q. In a coil of self inductance of

5

henry, the rate of change of current is

2

ampere per second, the e.m.f. induced in the coil is

The mutual inductance between two coils is 1.25 henry. If the current in the primary coil changes at a rate of 80 ampere/second, then the induced e.m.f. in the secondary coil is

Join BYJU'S Learning Program

A 10 henry inductor is carrying a current 2A. Rate at which the current be changed so that an e.m.f. of 100V is induced is

The correct option is B Given E=100V, L=10 H ∴100=10×dIdt or dIdt=10As−1

The correct option is B

Given $E = 100 V, L = 10 H$

$∴ 100 = 10 \times \frac{d I}{d t} o r \frac{d I}{d t} = 10 A s^{- 1}$