Question

A $10k\Omega$ resistor can be obtained by using

• A. $3k\Omega ,5k\Omega ,2k\Omega$ resistors in series
• B. $3k\Omega ,5k\Omega ,2k\Omega$ Resistors in parallel
• C. $3k\Omega ,5k\Omega$ in series and combination in parallel to $2k\Omega$ resistor in series
• D. $5k\Omega ,5k\Omega ,2k\Omega ,$ Resistors in series

Answer 1

The correct option is A $3k\Omega ,5k\Omega ,2k\Omega$ resistors in series

When three resistors are connected in series, the equivalent resistance is $R_{eq}=R_1+R_2+R_3$.

In the question, $R_1=3k\Omega$, $R_2=5k\Omega$, $R_3=2k\Omega$.

$\therefore R_{eq}=3+5+2=10k\Omega$