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Question

A 10−kg block is pulled in the vertical plane along a frictionless surface in the form of an arc of a circle of radius 10m.The applied force is 200N as shown in the figure.If the block started from rest at A,the velocity at B would be
712606_a97e7bbb858845deb711d1e9608f19dc.png

A
1.732 m/s
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B
17.32 m/s
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C
173.2 m/s
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D
none of these
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Solution

The correct option is C 17.32 m/s
Here, F is the external force, which results in tension T=F, along the direction of motion of the block, i.e. tangential to the circle.
Thus, Work done by F from A to B is W=F×πR3=200×π×103=2094J

Let the velocity of block at B as v.
Taking A as point of reference for potential energy calculations,
Initial mechanical energy at point A is, EA=0
Final mechanical energy at point B is, EB=mgR(1cos600)+12mv2
EB=10×10×10(10.5)+12×10×v2
EB=500+5v2

As work done by external force equals change in Mechanical Energy.
W=EBEA5v2=1594v=17.85 m/s

Nearest option is B

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