A 10−kg block is pulled in the vertical plane along a frictionless surface in the form of an arc of a circle of radius 10m.The applied force is 200N as shown in the figure.If the block started from rest at A,the velocity at B would be
A
1.732m/s
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B
17.32m/s
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C
173.2m/s
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D
none of these
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Solution
The correct option is C17.32m/s Here, F is the external force, which results in tension T=F, along the direction of motion of the block, i.e. tangential to the circle.
Thus, Work done by F from A to B is W=F×πR3=200×π×103=2094J
Let the velocity of block at B as v.
Taking A as point of reference for potential energy calculations,
Initial mechanical energy at point A is, EA=0
Final mechanical energy at point B is, EB=mgR(1−cos600)+12mv2
⟹EB=10×10×10(1−0.5)+12×10×v2
⟹EB=500+5v2
As work done by external force equals change in Mechanical Energy.