Question

A $10kg$ body is suspended by a rope. It is pulled aside till the string makes an angle of ${60}^{\circ }$ with respect to vertical and kept at rest in this position by applying a horizontal force. Find the magnitude of horizontal force.

• A. $10\sqrt{3}kgwt$
• B. $10\sqrt{2}kgwt$
• C. $5\sqrt{3}kgwt$
• D. $5\sqrt{2}kgwt$

Answer 1

The correct option is A $10\sqrt{3}kgwt$

Horizontal force $=mg\sin \theta$

$=mg\sin 60°$

$=10\times \sqrt{3}㎏wt$

$10\sqrt{3}㎏wt$

Hence, this is the answer.