A 10kg stone is suspended with a rope of breaking strength 30kg.wt. The minimum time in which the stone can be raised through a height 10m starting from rest is: (Taking g=10Nkg−1)
A
0.5s
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B
1.0s
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C
√23s
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D
2.0s
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Solution
The correct option is D1.0s Maximum acceleration allowed after which the rope breaks = Fmaxm
=30×1010=30m/s2
Acceleration due to gravity is already present due to suspension of stone.
Thus acceleration upto which the stone can be lifted with = amax−g=a=20m/s2