wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A 1.0m long metallic rod is rotated with an angular frequency of 400rads-1 about an axis normal to the rod passing through its one end. The other end of the rod is in contact with a circular metallic ring. A constant and uniform magnetic field of 0.5T parallel to the axis exists everywhere. Calculate the EMF developed between the center and the ring.


Open in App
Solution

Step 1: Given Data

Length of the rod L=1.0m

Angular frequency ω=400rads-1

A constant and uniform magnetic field B=0.5T

Step 2: Estimate the velocity

Velocity at the end of the rod is given as

v=Lω

The length at the center of the rod is L2.

Therefore, the velocity at the center of the rod is given as,

vC=Lω2

Step 3: Calculate the EMF

So, emf given at the center of the rod is,

ε=BLvC

=BL2ω2

Hence, the EMF developed between the center and the ring is

ε=0.5×12×4002

=100V

Hence, the EMF developed between the center and the ring is 100V.


flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Direction of Induced Current
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon