Question

A $10\mu F$ capacitor is charged to a $25$ volt of potential. The battery is disconnected and a pure $100$ m H coil is connected across the capacitor so that LC oscillations are set up. Calculate the maximum current in the coil.

Answer 1

$\frac{1}{2}L{I}_0^2=\frac{1}{2}\times {10}^{-5}\times (25{)}^2$

$I_0=25\times \sqrt{\frac{{10}^{-5}}{{10}^{-1}}}$

$I_0=0.25A$