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Question

A 10 ohm resistance, 5 mH coil and 10 μF capacitor are joined in series. When a suitable frequency alternating current source is joined to this combination, the circuit resonates. If the resistance is halved, the resonance frequency

A
remains unchanged
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B
is quadrupled
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C
is halved
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D
is doubled
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Solution

The correct option is A remains unchanged
Change in resonance frequency:
Let the resonant frequency be fr.
We know that,
fr=12πLC
Now fr does not depend upon resistance, so where resistance is halved, the resonance frequency remains unchanged.
Hence, option (C) is correct.

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