A 10ohm resistance, 5mH coil and 10μF capacitor are joined in series. When a suitable frequency alternating current source is joined to this combination, the circuit resonates. If the resistance is halved, the resonance frequency
A
remains unchanged
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B
is quadrupled
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C
is halved
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D
is doubled
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Solution
The correct option is A remains unchanged Change in resonance frequency:
Let the resonant frequency be fr.
We know that, fr=12π√LC
Now fr does not depend upon resistance, so where resistance is halved, the resonance frequency remains unchanged.
Hence, option (C) is correct.