A 10Ω resistance, 5mH coil and 10μF capacitor are joined in series. When a suitable frequency alternating current source is joined to this combination, the circuit resonates. If the resistance is halved, the resonance frequency:
A
is halved
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B
is doubled
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C
remains unchanged
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D
is quadrupled
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Solution
The correct option is C remains unchanged At resonance
f=12π√LC
Hence no effect of R. The resonance frequency remains same when R is changed.