Question

A $10$% solution of $HN{O}_3$ would be produced by dissolving $63g$ $HN{O}_3$ in how many $mL$ water?

• A. $100$
• B. $300$
• C. $567$
• D. $630$
• E. $1000$

Answer 1

Answer: (C)

$567$

Mol. wt of $HN{O}_3$ = 1 + 14 + 3 X 16 =63

10% sol of $HN{O}_3$ = ( 63 gm /wt of solution) X 100

=> 10 = 63/(wt of water+wt of $HN{O}_3$) X 100

=> wt of water+ wt of $HN{O}_3$ = 630

=> wt of water +63 = 630

=> wt of water = 630-63 = 567 gm

Density of water = 1 gm/ml

Vol of water in ml = 567 ml