A 10% solution of $H N O_{3}$ would be produced by dissolving 63 g $H N O_{3}$ in how many mL water?

100

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300

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567

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630

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1000

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Solution

The correct option is C 567
molar mass of $H N O_{3}$ $=$ $63 g / m o l e$
The question can only refer to a 10%m/m solution. From the data given it is not possible to calculate for a 10%m/v solution
10% m/m solution $=$ 63g in total mass 630g of solution
Therefore mass of $H_{2} O$ $=$ $630 - 63$ $=$ $567 g$
density of $H_{2} O$ $=$ $1 g / m l$
so volume $=$ $567 m l$

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