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Question

A 10 m long wire of resistance 20 Ω is connected in series with a battery of emf 3 V (negligible internal resistance) and a resistance of 10 Ω. Find the potential gradient along the wire

A
3 V/m
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B
0.2 V/m
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C
0.1 V/m
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D
0.3 V/m
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Solution

The correct option is B 0.2 V/m
potential gradient =potential difference across 20 Ωlength of 20 Ω wire
ϕ=(Rwire)×Il
Current I
=V(Rwire+Rexternal)=3(20+10)=330=0.1 A
ϕ=20×0.110=0.2 V/m

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