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Series Combination of Cells

A 10 V batter...

Question

A 10 V battery of negligible internal resistance is connected across a 200 V battery and a resistance of $38 ω$ as shown in the figure. Find the value of the current in circuit.

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Solution

The net potential difference applied across the resistor= $200 V - 10 V = 190 V$
The resistance of the resistor= $38 Ω$
Hence current through the resistor= $\frac{190 V}{38 Ω} = 5 A$

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