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Question

A 100 % efficiency transformer has 100 turns in the primary and 25 turm coil. If the current in the secondary coil is 4 A, then the current in the primary coil is

A
1 A
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B
4 A
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C
8 A
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D
16 A
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Solution

The correct option is D 16 A

Number of turns in the primary , Np = 100

Number of turns in the secondary , Ns = 25

Current in the secondary coil ,Is = 4 amp

we have to find out current in the primary coil ,Ip = ?

Ns/Np = Vs/Vp

Also , Vs × is = Vp × ip

Then, Ns/Np = Ip/is

100/25 =Ip/4

4 × 4 = Ip

Ip = 16 amp


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