A 100 g iron ball having velocity 10 m/s collides with a wall at an angle $30^{o}$ and rebounds with the same angle. If the period of contact between the ball and wall is 0.1 second, then the force experienced by the wall is

10 N

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100 N

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1.0 N

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0.1 N

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Solution

The correct option is A
10 N

During collision of ball with the wall horizontal momentum changes (vertical momentum remains constant)

$∴ F = \frac{C h a n g e i n h o r i z o n t a l m o m e n t u m}{T i m e o f c o n t a c t}$
$= \frac{2 P c o s θ}{0.1} = \frac{2 m v c o s θ}{0.1}$
$= \frac{2 \times 0.1 \times 10 \times c o s 60^{o}}{0.1} = 10 N$

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A 100 g iron ball having velocity 10 m/s collides with a wall at an angle 30o and rebounds with the same angle. If the period of contact between the ball and wall is 0.1 second, then the force experienced by the wall is

The correct option is A 10 N During collision of ball with the wall horizontal momentum changes (vertical momentum remains constant) ∴F=Change in horizontal momentumTime of contact =2P cosθ0.1=2mv cosθ0.1 =2×0.1×10×cos 60o0.1=10 N

A 100 g iron ball having velocity 10 m/s collides with a wall at an angle $30^{o}$ and rebounds with the same angle. If the period of contact between the ball and wall is 0.1 second, then the force experienced by the wall is