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Relation between Work Done and PE

A 100 kg bl...

Question

A $100$ kg block kept at the back of a truck moving with an acceleration of $2 m s^{- 2}$ there is no relative motion. What is the work done by the frictional force on the block as a truck is displaced by $2 m$ w.r.t Ground?

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Solution

Frictional force acting on block = ma = $100 \times 2 = 200 N$
work done by friction $= F \times D i s p l a c e m e n t = 200 \times 2 = 400 J$
here work is positive

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