Question

A 100 m cable is suspended vertically. At any point along the cable, the strain is proportional to the length of the cable below that point . If the strain at the top of the cable is 0.001 , Determine the total elongation of the cable .

• A. 0.05 m
• B. 0.10 m
• C. 0.20 m
• D. 0.40 m

Answer 1

The correct option is A 0.05 m


$e_{avg}=\frac{1}{2}\left(0.001\right)=0.0005$

$\therefore$ Total elongation = (e${}_{avg}\times L$)

= (0.0005 $\times 100$)

= 0.05 m