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Question

# A 100 mL solution containing AgNO3 was treated with excess of NaCl to precipitate the silver as AgCl completely. Determine the Ag+ concentration in original solution, if 5.7g AgCl was obtained.

A
0.03M
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B
0.05M
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C
0.12M
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D
0.30M
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E
0.40M
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Solution

## The correct option is E 0.40MAgNO3+NaCl→AgCl+NaNO3 The molar mass of AgCl is 108+35.5=143.5 g/mol.5.7 g AgCl corresponds to 5.7g143.5g/mol=0.040mol.The number of moles of Ag+ ions is equal to the number of moles of AgCl. It is 0.040 molesThe molar concentration is the ratio of the number of moles of Ag+ ions to total volume of solution in L.It is 0.040mol100mL×100mL1000mL=0.40 M.

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